Table 1: The different models of single-electron ion/atom.

 

Model ®

Bohr atom

Planetary

Relativistic

Planetary- Relativistic

Final

Planetary- Relativistic a-

 

Momentum

Le = hn/2p

Le + Lnu = hn/2p

Le = hn/2p

Le + Lnu = hn/2p

Le + Lnu = hn/2p

 

Centrifugal force

Fe = me0ve2/Re

-

Fe = me0ve2/Re

Fnu = M0vnu2/Rnu

F1 = me0ve2/(1 - ve2/c2)1/2Re

-

F1 = me0ve2/(1 - ve2/c2)1/2Re

F2 = M0vnu2/(1 - vnu2/c2)1/2Rnu

F1 = me0ve2/(1 - ve2/c2)1/2Re

F2 = M0vnu2/(1 - vnu2/c2)1/2Rnu

 

Coulomb force

FC = Ze2/[4pε0×Re2]

FC = Ze2/[4pε0×(Re+Rnu)2]

FC = Ze2/[4pε0×Re2]

FC=Ze2/[4pε0×(Re+Rnu)2]

FC = (Z+A×Z7/3)e2/[4pε0×(Re+Rnu)2]

A » -2.81×10-6

 

Electron

Ee = -meZ2e4/[8e02h2n2]

Ee= -meM2Z2e4/[(me+M)28e02h2n2]

Ee= me0c2×(1 - Z2e4/[4e02h2n2c2])1/2 - me0c2

Ee = me0c2×(1 - ve2/c2)1/2 - me0c2

Ee = me0c2×(1 - ve2/c2)1/2 - me0c2

 

Atomic nucleus

-

Enu = -me2M0Z2e4/[(me+M)28e0h2n2]

-

Enu = M0c2×(1 - vnu2/c2)1/2 - M0c2

Enu = M0c2×(1 - vnu2/c2)1/2 - M0c2

 

Electron- atomic nucleus bond

E = -meZ2e4/[8e0h2n2]

E = -meM0Z2e4/[8(me+M)e02h2n2]

E = me0c2×(1–Z2e4/[4e02h2n2c2])1/2 - me0c2

E = me0c2×(1 - ve2/c2)1/2 - me0c2 + M0c2×(1 - vnu2/c2)1/2 - M0c2

E = me0c2×(1 - ve2/c2)1/2 - me0c2 + M0c2×(1 - vnu2/c2)1/2 - M0c2

 

H b-

0.0539%

-0.0006%

0.0552%

0.00071%

0.000181%

 

Kr35+ b-

-1.6885%

-1.6891%

0.0689%

0.06822%

0.000189%

 

Maximum b-

-1.6885% (Kr35+)

-1.6891% (Kr35+)

0.0689% (Kr35+)

0.06822% (Kr35+)

0.00364% (Li2+)

 

Average c-

0.5764%

0.5763%

0.0336%

0.02978%

0.001157%

Here Re and Rnu are distances between center of mass and electron and atomic nucleus, me0 and M0 are the rest mass of electron and atomic nucleus, ve, vnu and v the speed of electron, atomic nucleus and sum of speed electron and atomic nucleus, Z the number of element, e the electrical charge, ε0 and h are the dielectric and Planck’s constants, c the speed of light. a- v = (Z + A×Z7/3)e2/[2nh ε0]; thβe = ve/c = {(1 - [2cos(j/3) + 1]/[3ch2β])1/2 - (1 - [2cos(j/3 + 2p/3) + 1]/[3ch2β])1/2 + (1 - [2cos(j/3+ 4p/3) + 1]/[3ch2β])1/2}/2 + thβ /2; j = arccos(1 - 54sh2β ch4β ch2β Msh2β M); chβ M = [M2/(M2 - me2)]1/2; shβ M = [me2/(M2 - me2)]1/2; chβ = 1/[1 - (v/c)2]1/2; shβ = (v/c)/[1 - (v/c)2]1/2 ; thβ nu = thβ - thβ e; b- 100%×(E - Iexperim) /Iexperim; c- 100%×S½E - Iexperim½/Iexperim)/N, N = 36.